Originally posted by David O'Meara: Then when you initialise your Comparator, pass in the list used for ordering. So basically, I have 2 ArrayLists (listA and listB). Solution based on bubble sort (same length required): If the object references should be the same, you can initialize listA new. For example, explain why your solution is better, explain the reasoning behind your solution, etc. A tree illustrates a hierarchical structure in contrast to other data structures such an array, stack, queue, and linked list, which are linear in nature. All rights reserved. Sign up for Infrastructure as a Newsletter. Let's say you have a listB list that defines the order in which you want to sort listA. How can I check before my flight that the cloud separation requirements in VFR flight rules are met? This is an old question but some of the answers I see posted don't actually work because zip is not scriptable. The answer of riza might be useful when plotting data, since zip(*sorted(zip(X, Y), key=lambda pair: pair[0])) returns both the sorted X and Y sorted with values of X. We can use the following methods to sort the list: Using stream.sorted () method Using Comparator.reverseOrder () method Using Comparator.naturalOrder () method Using Collections.reverseOrder () method Using Collections.sort () method Java Stream interface Java Stream interface provides two methods for sorting the list: sorted () method Here if the data type of Value is String, then we sort the list using a comparator. I mean swapItems(), removeItem(), addItem(), setItem() ?? Just remember Zx and Zy are tuples. Starting with the example input you provided: This is also known as the Schwartzian_transform after R. Schwartz who popularized this pattern in Perl in the 90s: Note that in this case Y and X are sorted and compared lexicographically. Once we have the list of values in a sorted manner, we build the HashMap again based on this new list. Why is "1000000000000000 in range(1000000000000001)" so fast in Python 3? That way, I can sort any list in the same order as the source list. Try this. rev2023.3.3.43278. You can checkout more examples from our GitHub Repository. The second issue is that if listA and listB do contain references to the same objects (which makes the first issue moot, of course), and they contain the same objects (as the OP implied when he said "reordered"), then this whole thing is the same as, And a third major issue is that by the end of this function you're left with some pretty weird side effects. Does this require that the values in X are unqiue? Overview Filtering a Collection by a List is a common business logic scenario. Linear regulator thermal information missing in datasheet, Short story taking place on a toroidal planet or moon involving flying, Identify those arcade games from a 1983 Brazilian music video, It is also probably wrong to have your class implements. Why is this sentence from The Great Gatsby grammatical? Does this require that the values in X are unqiue? 2013-2023 Stack Abuse. An efficient solution is to first create the mapping from the ID in the ids (your desired IDs order) to the index in that list: And then sort your list of people by the order of their id in this mapping: Note: if a person has an ID that is not present in the ids, they will be placed first in the list. - Hatefiend Since Comparator is a functional interface, we can use lambda expressions to write its implementation in a single line. On the Data tab of the Ribbon, in the Sort & Filter group, click Advanced. The toList() return the collector which collects all the input elements into a list, in encounter order. For bigger arrays / vectors, this solution with numpy is beneficial! Are there tables of wastage rates for different fruit and veg? It is stable for an ordered stream. Java List is similar to arrays except that the length of the list is dynamic and it comes in Java Collection framework. Sorting values of a dictionary based on a list. I fail to see where the problem is. you can leverage that solution directly in your existing df. It only takes a minute to sign up. You are using Python 3. Find centralized, trusted content and collaborate around the technologies you use most. If the elements are not comparable, it throws java.lang.ClassCastException. We can use the following methods to sort the list: Java Stream interface provides two methods for sorting the list: Stream interface provides a sorted() method to sort a list. All the elements in the list must implement Comparable interface, otherwise IllegalArgumentException is thrown. I suspect the easiest way to do this will be by writing a custom implementation of java.util.Comparator which can be used in a call to Collections.sort(). However, some may lead to under-performing solutions if not done properly. That's O(n^2 logn)! This solution is poor when it comes to storage. Note: the key=operator.itemgetter(1) solves the duplicate issue, zip is not subscriptable you must actually use, If there is more than one matching it gets the first, This does not solve the OPs question. If you have 2 lists of identical number of items and where every item in list 1 is related to list 2 in the same order (e.g a = 0 , b = 1, etc.) Specifically, we're using the comparingInt() method, and supplying the user's age, via the User::getAge method reference. Connect and share knowledge within a single location that is structured and easy to search. If you already have a dfwhy converting it to a list, process it, then convert to df again? I can resort to the use of for constructs but I am curious if there is a shorter way. "After the incident", I started to be more careful not to trip over things. Theoretically Correct vs Practical Notation. http://scienceoss.com/sort-one-list-by-another-list/. A example will show this. With this method: Sorting a 1000 items list 100 times improves speed 10 times on my This will sort all factories according to their price. Browse other questions tagged, Where developers & technologists share private knowledge with coworkers, Reach developers & technologists worldwide. Zip the two lists together, sort it, then take the parts you want: Also, if you don't mind using numpy arrays (or in fact already are dealing with numpy arrays), here is another nice solution: I found it here: A:[c,b,a] [[name=a, age=age11], [name=a, age=age111], [name=a, age=age1], [name=b, age=age22], [name=b, age=age2], [name=c, age=age33], [name=c, age=age3]]. To learn more about comparator, read this tutorial. The solution below is the most efficient in this case: Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. They store items in key, value pairs. Has 90% of ice around Antarctica disappeared in less than a decade? http://scienceoss.com/sort-one-list-by-another-list/. - the incident has nothing to do with me; can I use this this way? unit tests. All rights reserved. I think that the title of the original question is not accurate. This class has two parameters, firstName and lastName. @Jack Yes, like what I did in the last example. Premium CPU-Optimized Droplets are now available. Wed like to help. Take a look at this solution, may be this is what you are trying to achieve: O U T P U T It is the method of Java Collections class which belong to a java.lang package. 1. The Collections (Java Doc) class (part of the Java Collection Framework) provides a list of static methods which we can use when working with collections such as list, set and the like. To sort the String values in the list we use a comparator. We can easily reverse this order as well, simply by chaining the reversed() method after the comparingInt() call: While Comparators produced by methods such as comparing() and comparingInt(), are super-simple to work with and only require a sorting key - sometimes, the automated behavior is not what we're looking for. See more examples here. One with the specific order the lists should be in (listB) and the other has the list of items (listA). @RichieV I recommend using Quicksort or an in-place merge sort implementation. more_itertools has a tool for sorting iterables in parallel: I actually came here looking to sort a list by a list where the values matched. I like having a list of sorted indices. 1. Is there a solution to add special characters from software and how to do it. If they are already numpy arrays, then it's simply. In Python 2, zip produced a list. vegan) just to try it, does this inconvenience the caterers and staff? Staging Ground Beta 1 Recap, and Reviewers needed for Beta 2, Sorting a list in Python using the result from sorting another list, How to rearrange one list based on a second list of indices, How to sort a list according to another list? We will use a simple sorting algorithm, Bubble Sort, to sort the elements of a linked list in ascending order below. Once streamed, we can run the sorted() method, which sorts these integers naturally. Short story taking place on a toroidal planet or moon involving flying. P.S. We first get the String values in a list. @RichieV I recommend using Quicksort or an in-place merge sort implementation. @Debacle What operations are allowed on the backend over listA? In this tutorial, we'll compare some filtering implementations and discuss their advantages and drawbacks. - the incident has nothing to do with me; can I use this this way? 2) Does listA and listB contain references to the same objects, or just objects that are equivalent with equals()? Styling contours by colour and by line thickness in QGIS. Sorting list according to corresponding values from a parallel list [duplicate]. For example, the following code creates a list of Student and in-place . Connect and share knowledge within a single location that is structured and easy to search. How do I split a list into equally-sized chunks? Basically, this answer is nonsense. Does a summoned creature play immediately after being summoned by a ready action? Key and Value can be of different types (eg - String, Integer). originalList always contains all element from orderedList, but not vice versa. Warning: If you run it with empty lists it crashes. Here, the sorted() method also follows the natural order, as imposed by the JVM. Python. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. Sorting Strings in reverse order is as simple as sorting integers in reverse order: In all of the previous examples, we've worked with Comparable types. Can airtags be tracked from an iMac desktop, with no iPhone? Sorting Strings is a tiny bit different, since it's a bit less intuitive on how to compare them. Another solution that may work depending on your setting is not storing instances in listB but instead indices from listA. Sorting in Natural Order and Reverse Order ', not 'How to sorting list based on values from another list?'. Linear Algebra - Linear transformation question, Acidity of alcohols and basicity of amines, Is there a solution to add special characters from software and how to do it. Your problem statement is not very clear. If the data is related then the data should be stored together in a simple class. Another alternative, combining several of the answers. test bed for array based list implementation, Reading rows based on column value in POI. To avoid having a very inefficient look up, you should index the items in listB and then sort listA based on it. "Sunday" => 0, , "Saturday" => 6. People will search this post looking to sort lists not dictionaries. I want to create a new list using list1 and list2 sorted by age (descending), but I also another condition that is better explained with an example: . That's easily managed with an index list: Since the decorate-sort-undecorate approach described by Whatang is a little simpler and works in all cases, it's probably better most of the time. Speed improvement on JB Nizet's answer (from the suggestion he made himself). The nature of simulating nature: A Q&A with IBM Quantum researcher Dr. Jamie We've added a "Necessary cookies only" option to the cookie consent popup. We can use Collections.sort() method to sort a list in the natural ascending order. Browse other questions tagged, Start here for a quick overview of the site, Detailed answers to any questions you might have, Discuss the workings and policies of this site. May be not the full listB, but something. O(n) look up happening roughly O(nlogn) times? The solution assumes that all the objects in the list to sort have distinct keys. Better example data would be quite helpful, too. An in-place sort is preferred whenever possible. What is the shortest way of sorting X using values from Y to get the following output? You can use this generic comparator to sort list based on the the other list. Did any DOS compatibility layers exist for any UNIX-like systems before DOS started to become outmoded? All rights reserved. Wed like to help. How To Install Grails on an Ubuntu 12.04 VPS, Simple and reliable cloud website hosting, New! Most of the solutions above are complicated and I think they will not work if the lists are of different lengths or do not contain the exact same items. As each pair of strings are passed in for comparison, convert them into ints using originalList.indexOf, except that if the index is -1, change the index to originalList.size() Compare the two ints. 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The end result should be list Y being untouched and list X being changed into the expected solution without ever having to create a temp list. Learn more about Stack Overflow the company, and our products. You can create a pandas Series, using the primary list as data and the other list as index, and then just sort by the index: This is helpful when needing to order a smaller list to values in larger. The signature of the method is: T: Comparable type of element to be compared. 12 is less than 21 and no one from L2 is in between. Disconnect between goals and daily tasksIs it me, or the industry? Otherwise, I see a lot of answers here using Collections.sort(), however there is an alternative method which is guaranteed O(2n) runtime, which should theoretically be faster than sort's worst time complexity of O(nlog(n)), at the cost of 2n storage. To learn more, see our tips on writing great answers. What video game is Charlie playing in Poker Face S01E07? Your compare methods are currently doing: This can be written more concisely with the built-in Double.compare (since Java 7), which also properly handles NaN, -0.0 and 0.0, contrary to your current code: Note that you would have the same implementation for the Comparator. Why did Ukraine abstain from the UNHRC vote on China? By clicking Post Your Answer, you agree to our terms of service, privacy policy and cookie policy. I can resort to the use of for constructs but I am curious if there is a shorter way. Though it might not be obvious, this is exactly equivalent to, This is correct, but I'll add the note that if you're trying to sort multiple arrays by the same array, this won't neccessarily work as expected, since the key that is being used to sort is (y,x), not just y. Did this satellite streak past the Hubble Space Telescope so close that it was out of focus? Edit: Fixed this line return this.left.compareTo(o.left);. In this quick tutorial, we'll learn how to find items from one list based on values from another list using Java 8 Streams. This solution is poor when it comes to storage. Not the answer you're looking for? Lets look at a quick example to sort a list of strings. If changes are possible, you would need to somehow listen for changes to the original list and update the indices inside the custom list. Making statements based on opinion; back them up with references or personal experience. People will search this post looking to sort lists not dictionaries. Check out our offerings for compute, storage, networking, and managed databases. Oh, ignore, I can do sorted(zip(Index,X,Y,Z)) too. Mark should be before Robert, in a list sorted by name, but in the list we've sorted previously, it's the other way around. The nature of simulating nature: A Q&A with IBM Quantum researcher Dr. Jamie We've added a "Necessary cookies only" option to the cookie consent popup. When we try to use sort over a zip object. It throws NullPointerException when comparing null. Just remember Zx and Zy are tuples. "After the incident", I started to be more careful not to trip over things. How to sort one list and re-sort another list keeping same relation python? Use MathJax to format equations. Can you write oxidation states with negative Roman numerals? All times above are in ranch (not your local) time. If you notice the above examples, the Value objects implement the Comparator interface. There are plenty of ways to achieve this. QED. Did any DOS compatibility layers exist for any UNIX-like systems before DOS started to become outmoded? For more information on how to set\use the key parameter as well as the sorted function in general, take a look at this. All of the values at the end of the list will be in their order dictated by the list2. If a law is new but its interpretation is vague, can the courts directly ask the drafters the intent and official interpretation of their law? Guide to Java 8 Collectors: groupingByConcurrent(), Java 8 - Difference Between map() and flatMap(), Java: Finding Duplicate Elements in a Stream, Java - Filter a Stream with Lambda Expressions, Guide to Java 8 Collectors: averagingDouble(), averagingLong() and averagingInt(), Make Clarity from Data - Quickly Learn Data Visualization with Python, // Constructor, getters, setters and toString(), Sorting a List of Integers with Stream.sorted(), Sorting a List of Integers in Descending Order with Stream.sorted(), Sorting a List of Strings with Stream.sorted(), Sorting Custom Objects with Stream.sorted(Comparator